They Will Eat Cake

Nimesikia na huyo Engineer. So we weigh less on the Equator? Because of the curvature of the earth and not gravitational pull? I am going back to school coz it looks like there's much I missed.
Wacha @Aviator alete zile formula zake. Aanze na Fourier's

f(x)=12+∞∑n=11–(–1)nπnsinnx. f ( x ) = 1 2 + ∑ n = 1 ∞ 1 – ( – 1 ) n π n sin ⁡

Amalizie na Euler's
e^{ix}=\cos x+i\sin x

Ndio utajua "qu'ils mangent de la brioche",
 
Eng. Mohamed is wrong.
Given any weight and the gravitational constant, you can derive the mass, which is a constant. These spring scales work this way to get mass. Note that the spring won't work in Mars unless recalibrated.

The variation of g at any point on earth is negligible for all practical purposes, therefore the spring scale is accurate.
 
Eng. Mohamed is wrong.
Given any weight and the gravitational constant, you can derive the mass, which is a constant. These spring scales work this way to get mass. Note that the spring won't work in Mars unless recalibrated.

The variation of g at any point on earth is negligible for all practical purposes, therefore the spring scale is accurate.
I think he just wanted to discombobulate the fellow and others who may have wanted to spread the message to expose the fraud.
 
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